3.8x=2x^2-98x+5

Solution for 3.8x=2x^2-98x+5 equation:

3.8x=2x^2-98x+5

We move all terms to the left:

3.8x-(2x^2-98x+5)=0

We get rid of parentheses

-2x^2+3.8x+98x-5=0

We add all the numbers together, and all the variables

-2x^2+101.8x-5=0

a = -2; b = 101.8; c = -5;
Δ = b2-4ac
Δ = 101.82-4·(-2)·(-5)
Δ = 10323.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101.8)-\sqrt{10323.24}}{2*-2}=\frac{-101.8-\sqrt{10323.24}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101.8)+\sqrt{10323.24}}{2*-2}=\frac{-101.8+\sqrt{10323.24}}{-4}
$